6x^2+7x-90=0

Solution for 6x^2+7x-90=0 equation:

6x^2+7x-90=0

a = 6; b = 7; c = -90;
Δ = b2-4ac
Δ = 72-4·6·(-90)
Δ = 2209
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2209}=47$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-47}{2*6}=\frac{-54}{12}
=-4+1/2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+47}{2*6}=\frac{40}{12}
=3+1/3
$